(2x+1)(3x^2+2x-5)=0

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Solution for (2x+1)(3x^2+2x-5)=0 equation: 


Simplifying
(2x + 1)(3x2 + 2x + -5) = 0

Reorder the terms:
(1 + 2x)(3x2 + 2x + -5) = 0

Reorder the terms:
(1 + 2x)(-5 + 2x + 3x2) = 0

Multiply (1 + 2x) * (-5 + 2x + 3x2)
(1(-5 + 2x + 3x2) + 2x * (-5 + 2x + 3x2)) = 0
((-5 * 1 + 2x * 1 + 3x2 * 1) + 2x * (-5 + 2x + 3x2)) = 0
((-5 + 2x + 3x2) + 2x * (-5 + 2x + 3x2)) = 0
(-5 + 2x + 3x2 + (-5 * 2x + 2x * 2x + 3x2 * 2x)) = 0
(-5 + 2x + 3x2 + (-10x + 4x2 + 6x3)) = 0

Reorder the terms:
(-5 + 2x + -10x + 3x2 + 4x2 + 6x3) = 0

Combine like terms: 2x + -10x = -8x
(-5 + -8x + 3x2 + 4x2 + 6x3) = 0

Combine like terms: 3x2 + 4x2 = 7x2
(-5 + -8x + 7x2 + 6x3) = 0

Solving
-5 + -8x + 7x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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